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chapters/fundamentals/examples.tex
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chapters/fundamentals/examples.tex
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% !TeX root = ../../script.tex
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\documentclass[../../script.tex]{subfiles}
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\begin{document}
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\section[Examples of the Stationary Schrödinger Equation]{Examples of the Stationary Schrödinger Equation}
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We now want to solve the Schrödinger equation
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\[
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\frac{-\hbar^2}{2m} \dv[2]{\psi}{x} + \epot\psi = E\psi
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\]
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for a few simple, one-dimensional problems. These examples will illustrate the description of classical particles as waves and the following physical consequences.
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\subsection{The Free Particle}
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A particle is said to be free, if it is moving in a constant potention $\phi_0$, because then $\vec{F} = -\grad{\epot}$ means that no forces are acting on the particle.
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Through a suitable choice of the zero point energy we can set $\phi_0 = 0$, i.e. $\epot = 0$, and thus get the Schrödinger equation for a free particle
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\begin{equation}\label{eq:onedschroedinger}
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\frac{-\hbar^2}{2m} \dv[2]{\psi}{x} = E\psi
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\end{equation}
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The total energy $E = \ekin + \epot$ is because of $\epot$ now
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\[
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E = \frac{p^2}{2m} = \frac{\hbar^2 k^2}{2m}
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\]
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Thus~\eqref{eq:onedschroedinger} gets reduced to
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\[
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\dv[2]{\psi}{x} = -k^2 \psi
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\]
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which has the general solution
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\begin{equation}\label{eq:onedsolution}
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\psi(x) = Ae^{ikx} + Be^{-ikx}
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\end{equation}
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The time-dependent wave function
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\begin{equation}
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\psi(x, t) = \psi(x) \cdot e^{-i\omega t} = Ae^{i(kx - \omega t)} + Be^{-i(kx + \omega t)}
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\end{equation}
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represents the superposition of a planar wave travelling in the $+x$ and $-x$ direction.
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The coefficients $A$ and $B$ are the amplitudes of those waves, which are determined by the boundary conditions.
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For example, the wave function of electrons which are emitted from a cathode in $+x$ direction towards a detector, will have $B = 0$, since there are no particles moving in $-x$.
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From this experimental setup we know that the electrons are found along the length $L$ of the path between cathode and detector. This means their wave function can only be different from zero in this region of space.
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Using the normalization condition we get
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\begin{align*}
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&\int_0^L \abs{\psi(x)}^2 \dd{x} = 1 \\
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&\implies A^2 \cdot L = 1 \implies A = \frac{1}{\sqrt{L}}
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\end{align*}
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To determine the location of a particle at time $t$ more accurately, we will have to construct \textit{wave packets} in place of planar waves~\eqref{eq:onedsolution}
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\begin{equation}
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\psi(x, t) = \int_{k_0 - \Delta k / 2}^{k_0 + \Delta k / 2} A(k) e^{i(kx - \omega t)} \dd{k}
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\end{equation}
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The location uncertainty of this packet at $t = 0$ is
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\[
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\Delta x \ge \frac{\hbar}{2 \Delta p_x} = \frac{1}{2\Delta k}
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\]
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and depends on the pulse width $\Delta p_x = \hbar \Delta k$. The larger $k$ is, the more certainly $\Delta x(t = 0)$ can be determined, but the faster the wave packet spreads.
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Experimentally, this can be illustrated as follows: If we apply a short voltage pulse to the cathode at time $t = 0$, then electrons can start travelling towards the detector at this instance.
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The emitted electrons have a velocity distribution $\Delta v$, such that electrons with differing velocities $v$ will not necessarily be in the same location $x$ at a later point in time $t$.
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Instead they are spread over the interval $\Delta x(t) = t \cdot \Delta v$. The velocity distribution is described by $\Delta v \propto \Delta k$ of the wave packet, such that the location uncertainty $\Delta x$
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\[
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\dv{(\Delta x(t))}{t} = \Delta v(t = 0) = \frac{\hbar}{m} \Delta k(t = 0)
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\]
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changes proportionally to the initial impulse uncertainty.
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\end{document}
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27
chapters/fundamentals/fundamentals.tex
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chapters/fundamentals/fundamentals.tex
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% !TeX root = ../script.tex
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\documentclass[../../script.tex]{subfiles}
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\begin{document}
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\chapter{Fundamentals of Quantum Physics}
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\minitoc
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\vspace*{\fill}\par
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\pagebreak
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Due to the uncertainty principle, location and impulse of an atomic particle cannot be both stated with arbitrairy precision.
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The classic trajectory, represented in the model of mass points by a well-defined curve in space $\vec{r}(t)$, is replaced by the probability
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\begin{equation}
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W(x, y, z, t) \dd{v} = \abs{\psi(x, y, z, t)}^2 \dd{V}
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\end{equation}
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to find the particle in the volume element $\dd{V} = \dd{x}\dd{y}\dd{z}$ at the time $t$. This probability depends on the absolute square of the matter wave function $\psi(x, y, z, t)$.
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In this chapter we wnat to show how this wave function can be calculated for simple examples. These examples will also demonstrate the physical fundamentals of quantum mechanics and its
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differences to classical particle mechanics, elaborate on the concept of \textit{quantum numbers} and show under which conditions quantum mechanical results can be transitioned into classical physics.
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This is supposed to clarify that classic (i.e.\ pre-quantum) mechanics are contained in quantum mechanics as a limiting case for very small de Broglie wavelengths $\lambda_{dB} \rightarrow 0$.
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These examples should also demonstrate that almost all insights of quantum mechanics are already known in classic wave optics. This means: the actual novel concepts in quantum mechanics
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is the description of classic particles with matter waves. The deterministic description of the temporal development of location and impulse of a particle is thus replaced with a statistical
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treatment, by which we can only discuss probabilities of the results of a measurement. A fundamental uncertainty occurs when we observe location and impulse at the same time.
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\subfile{schroedinger.tex}
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\subfile{examples.tex}
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\end{document}
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chapters/fundamentals/schroedinger.tex
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chapters/fundamentals/schroedinger.tex
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% !TeX root = ../../script.tex
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\documentclass[../../script.tex]{subfiles}
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\begin{document}
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\section[The Schrödinger Equation]{The Schrödinger Equation}
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In this section we will outline the fundamental equation of quantum mechanics, which was established by \textit{Erwin Schrödinger} (1887--1961) in 1926.
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The solutions of this equation are the desired wave functions $\psi(x, y, z, t)$. However, these solutions can only be derived in analytical form for a few very simple physical problems.
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Very fast computers are usually able to numerically compute solutions for complex problems.
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First, we will consider the mathematically simplest case.A free particle of mass $m$ which moves at a constant velocity $\vec{v}$ in direction $x$.
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With $\vec{p} = \hbar\vec{k}$ and $E = \hbar \omega = \ekin$ (because $\epot = 0$), we know the wave function must be of the form
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\begin{equation}\label{eq:wavefuncform}
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\psi(x, t) = Ae^{i(kx-\omega t)} = Ae^{(i/\hbar)(px-\ekin t)}
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\end{equation}
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Here we use the fact that $\ekin = p^2 / 2m$, which is the kinetic energy of the particle. Since the mathematical representation is absolutely identical to that of an electromagnetic wave,
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it makes sense to start with the wave equation
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\begin{equation}\label{eq:1dwaveeq}
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\pdv[2]{\psi}{x} = \frac{1}{u^2} \pdv[2]{\psi}{t}
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\end{equation}
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for waves propagating with phase velocity $u$ in direction $x$. For \textit{stationary} problems where $\vec{p}$ and $E$ are time-independent the wave function can be split into a
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strictly location-dependent factor $\psi(x) = Ae^{ikx}$, and a strictly time-dependent phase factor $e^{-i\omega t}$. Thus we can write
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\begin{equation}\label{eq:splitwave}
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\psi(x, t) = \psi(x) \cdot e^{-i\omega t} = A e^{ikx} \cdot e^{-i\omega t}
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\end{equation}
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If we use the ansatz~\eqref{eq:splitwave} in the wave equation~\eqref{eq:1dwaveeq}, and the fact that $k^2 = p^2 / \hbar^2 = 2m\ekin/\hbar^2$, we get the equations
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\begin{equation}\label{eq:values}
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\begin{split}
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&\pdv[2]{\psi}{x} = -k^2\psi = -\frac{2m}{k} \cdot \ekin \cdot \psi \\
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&\pdv[2]{\psi}{t} = -\omega^2 \psi
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\end{split}
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\end{equation}
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Comparison with~\eqref{eq:1dwaveeq} gives us
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\[
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u^2 = \frac{\omega^2}{k^2} \implies u = \frac{\omega}{k}
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\]
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Note that the particle velocity $v_\text{P} = v$
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\[
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v = \frac{p}{m} = \frac{\hbar k}{m} = \pdv{\omega}{k}
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\]
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is different from the phase velocity $u = v_{\text{ph}} = \omega / k$.
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In the general case the particle can move in a force field. If it is conservative then we can assign each point a potential energy, with the condition that the total energy $E = \ekin + \epot$ remains constant.
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Using $\ekin = E - \epot$ and~\eqref{eq:values} we then receive the one-dimensional stationary Schrödinger equation
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\begin{tcolorbox}[ams equation]
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\frac{-\hbar^2}{2m} \pdv[2]{\psi}{x} + \epot\psi = E\psi
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\end{tcolorbox}
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For the general case where the particle is moving freely in three-dimensional space we can use the three-dimensional wave equation
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\[
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\laplacian\psi = \frac{1}{u^2} \pdv[2]{\psi}{t}
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\]
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and the ansatz $\psi(x, y, z, t) = \psi(x, y, z) \cdot e^{-i\omega t}$, we can establish the three-dimensional stationary Schrödinger equation
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\begin{tcolorbox}[ams equation]\label{eq:stationaryschroedinger}
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\frac{-\hbar^2}{2m} \laplacian \psi = \epot \psi = E \psi
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\end{tcolorbox}
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If we differentiate~\eqref{eq:wavefuncform} partially for time we receive
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\[
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\pdv{\psi}{t} = -\frac{i}{h} \ekin \cdot \psi
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\]
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and with~\eqref{eq:values} we can find the time-dependent equation for a free particle with $\epot = 0$ (i.e. $\ekin = \const$)
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\begin{equation}
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-\frac{\hbar^2}{2m} \pdv[2]{\psi(x, t)}{x} = i\hbar \pdv{\psi(x, t)}{t}
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\end{equation}
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The three-dimensional representation is then
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\begin{tcolorbox}[ams equation]
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-\frac{\hbar^2}{2m} \laplacian \psi(\vec{r}, t) = i\hbar \pdv{\psi(\vec{r}, t)}{t}
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\end{tcolorbox}
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There are some remarks to be made:
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\begin{itemize}
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\item In this ``derivation'' we have used the de Broglie-relationship $\vec{p} = \hbar \vec{k}$, which is only supported by experiments and has no mathematical justification.
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\item The law of conservation of energy of quantum mechanics is $E\psi = \ekin\psi + \epot\psi$. Like in classical mechanics, there is no derivation for this law, and is accepted as truth from experience.
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\item While electromagnetic waves have a linear dispersion relation $\omega(k) = kc$, the matter wave $\psi(\vec{r}, t)$ of a free particle has a \textit{quadratic} dispersion relation $\omega(k) = (\hbar/2m) \cdot k^2$. This results from $E = \hbar\omega = p^2/2m$.
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\item The Schrödinger equations are a \textit{linear} homogeneous differential equation. Because of this, different solutions of the equation can be superpositioned. This means, if $\psi_1$ and $\psi_2$ are solutions to the equation, then $\psi_3 = a\cdot\psi_1 + b\cdot\psi_2$ is also a solution.
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\item Since the time-dependent Schrödinger equation is a complex equation, the wave functions $\psi$ may also be complex. The absolute square $\abs{\psi}^2$ however, which represents the probability of the presence of a particle, is always real.
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\end{itemize}
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For non-stationary problems (i.e. $E = E(t)$ and $p = p(t)$), the dispersion relation $\omega(t)$ also becomes time-dependent. This means that $\partial^2\psi/\partial t^2$ can no longer be written as $-\omega^2 \psi$, and cannot be derived from the wave equation for matter waves of particles.
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Schrödinger postulated (!), that even for time-dependent potential energy $\epot(\vec{r}, t)$ the equation
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\begin{tcolorbox}[ams equation]\label{eq:schroedinger}
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\frac{-\hbar^2}{2m} \laplacian \psi(\vec{r}, t) + \epot(\vec{r}, t) \psi(\vec{r}, t) = i\hbar\pdv{\psi(\vec{r}, t)}{t}
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\end{tcolorbox}
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holds. The general time-dependent Schrödinger equation has since been verified in numerous experiments, and is generally considered correct, even if no mathematical justification exists.
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This equation is the fundamental equation of quantum mechanics.
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For stationary problems we can separate $\psi(\vec{r}, t)$ into $\psi(\vec{r}, t) = \psi(\vec{r}) \cdot e^{-i(E/\hbar) \cdot t}$. Inserting this into~\eqref{eq:schroedinger} yields the
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stationary Schrödinger equation~\eqref{eq:stationaryschroedinger} for $\psi(\vec{r})$.
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\end{document}
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script.tex
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\usepackage{tikz, pgfplots}
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\usepackage{kbordermatrix}
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\usepackage{fancyhdr}
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\usepackage[most]{tcolorbox}
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\usepackage{pdfpages}
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\usepackage[arrowdel]{physics}
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\usetikzlibrary{calc,trees,decorations.markings,positioning,arrows,fit,shapes,angles,patterns}
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version={4.0},
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]{doclicense}
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\tcbset{colback=yellow!10!white, colframe=red!50!black,
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highlight math style= {enhanced, %<-- needed for the ’remember’ options
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colframe=red,colback=red!10!white,boxsep=0pt}
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}
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\usepackage{subfiles}
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\DeclareMathOperator{\const}{const}
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\newcommand{\energy}[1]{E_{\text{#1}}}
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\newcommand{\ekin}{\energy{kin}}
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\newcommand{\epot}{\energy{pot}}
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\renewcommand{\vec}{\vb*}
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\renewcommand{\laplacian}{\Delta}
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\begin{document}
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\begin{titlepage}
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\begin{center}
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urlcolor=black
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}
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\subfile{chapters/fundamentals/fundamentals.tex}
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\pagestyle{headings}
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\end{document}
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