From 69f8e0bf74c6ecd591330d90f324f1a3bf57a683 Mon Sep 17 00:00:00 2001
From: Lauchmelder23 <Robert-Altner@t-online.de>
Date: Sun, 14 Oct 2018 16:15:03 +0200
Subject: [PATCH] Edited Problem 18 Added Problem 20

---
 Problem_018.py |  5 -----
 Problem_20.py  | 25 +++++++++++++++++++++++++
 2 files changed, 25 insertions(+), 5 deletions(-)
 create mode 100644 Problem_20.py

diff --git a/Problem_018.py b/Problem_018.py
index b5f86fc..896518b 100644
--- a/Problem_018.py
+++ b/Problem_018.py
@@ -48,11 +48,6 @@ triangle = "75 \n\
 63 66 04 68 89 53 67 30 73 16 69 87 40 31 \n\
 04 62 98 27 23 09 70 98 73 93 38 53 60 04 23 \n"
 
-other = "3 \n\
-7 4 \n\
-2 4 6 \n\
-8 5 9 3 \n"
-
 tri = []
 temp = []
 tempstr = ''
diff --git a/Problem_20.py b/Problem_20.py
new file mode 100644
index 0000000..01b75c0
--- /dev/null
+++ b/Problem_20.py
@@ -0,0 +1,25 @@
+######################################################################
+# n! means n × (n − 1) × ... × 3 × 2 × 1
+#
+# For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,
+# and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.
+#
+# Find the sum of the digits in the number 100!
+######################################################################
+
+def factorial(x):
+    if x is 1:
+        return x
+    else:
+        return x * factorial(x - 1)
+
+
+number = str(factorial(100))
+sum = 0
+
+for c in number:
+    sum += int(c)
+
+print(sum)
+
+# Solution: