Added Problem 17

Edited Problem 16

Problem_016.py

@@ -12,4 +12,4 @@ for c in number:
 
 print(sum)
 
-# Solution:
+# Solution: 1366

Problem_017.py

@@ -0,0 +1,52 @@
+######################################################################
+# If the numbers 1 to 5 are written out in words: one, two, three, four, five,
+# then there are 3 + 3 + 5 + 4 + 4 = 19 letters used in total.
+#
+# If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be used?
+#
+#
+# NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23
+# letters and 115 (one hundred and fifteen) contains 20 letters. The use of "and" when writing out
+# numbers is in compliance with British usage.
+######################################################################
+
+ones = ["ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"]
+special_tens = ["TEN", "ELEVEN", "TWELVE", "THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN",
+                "NINETEEN"]
+tens = ["TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"]
+hundreds = ["ONEHUNDREDAND", "TWOHUNDREDAND", "THREEHUNDREDAND", "FOURHUNDREDAND", "FIVEHUNDREDAND", "SIXHUNDREDAND",
+            "SEVENHUNDREDAND", "EIGHTHUNDREDAND", "NINEHUNDREDAND"]
+
+
+
+letter_count = 0
+for one in ones:
+    letter_count += len(one)
+
+for ten in special_tens:
+    letter_count += len(ten)
+
+for ten in tens:
+    letter_count += len(ten)
+    for one in ones:
+        letter_count += len(one) + len(ten)
+
+for hundred in hundreds:
+    letter_count += len(hundred) - 3
+
+    for one in ones:
+        letter_count += len(hundred) + len(one)
+
+    for ten in special_tens:
+        letter_count += len(hundred) + len(ten)
+
+    for ten in tens:
+        letter_count += len(hundred) + len(ten)
+        for one in ones:
+            letter_count += len(hundred) + len(ten) + len(one)
+
+letter_count += len("ONETHOUSAND")
+
+
+print(letter_count)
+# Solution: 21124