28 lines
849 B
Python
28 lines
849 B
Python
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######################################################################
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# The sum of the squares of the first ten natural numbers is,
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#
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# 1² + 2² + ... + 10² = 385
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# The square of the sum of the first ten natural numbers is,
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#
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# (1 + 2 + ... + 10)² = 55² = 3025
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# Hence the difference between the sum of the squares of the first ten
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# natural numbers and the square of the sum is 3025 − 385 = 2640.
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#
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# Find the difference between the sum of the squares of the first one
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# hundred natural numbers and the square of the sum.
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#
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######################################################################
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sum_of_squares = 0
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square_of_sums = 0
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for i in range(0, 101):
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sum_of_squares += pow(i, 2)
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square_of_sums += i
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square_of_sums = pow(square_of_sums, 2)
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difference = square_of_sums - sum_of_squares
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print(difference)
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# Solution: 25164150
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